There is a robot on an m x n
grid. The robot is initially located at the top-left corner (i.e., grid[0][0]
). The robot tries to move to the bottom-right corner (i.e., grid[m - 1][n - 1]
). The robot can only move either down or right at any point in time.
Given the two integers m
and n
, return the number of possible unique paths that the robot can take to reach the bottom-right corner.
The test cases are generated so that the answer will be less than or equal to 2 * 109
.
Example 1:
Input: m = 3, n = 7 Output: 28
Example 2:
Input: m = 3, n = 2 Output: 3 Explanation: From the top-left corner, there are a total of 3 ways to reach the bottom-right corner: 1. Right -> Down -> Down 2. Down -> Down -> Right 3. Down -> Right -> Down
Constraints:
1 <= m, n <= 100
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class Solution { | |
public: | |
int uniquePaths(int m, int n) { | |
int dp[100][100] = {0}; | |
dp[0][0] = 1; | |
for(int i = 0; i < m; i++) { | |
for(int j = 0; j < n; j++){ | |
if(i > 0) dp[i][j] += dp[i-1][j]; | |
if(j > 0) dp[i][j] += dp[i][j-1]; | |
} | |
} | |
return dp[m - 1][n - 1]; | |
} | |
}; |
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